Solve for x in ($4^3)^x$ = $\frac{1}{64}$

Solve for x in ($4^3)^x$ = $\frac{1}{64}$

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($4^3)^x$ = $\frac{1}{64}$,

($4^3)^x \; = 64^{-1}$

$4^{3x}$ = $4^{-3}$ equate the powers

3x = -3;

x = -1

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johnmulu answered the question on June 12, 2017 at 11:59

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